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Home » x^3 + y^3 = (x + y)(x^2 - xy + y^2) - Appfinity Technologies

x^3 + y^3 = (x + y)(x^2 - xy + y^2) - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Now, note that \(x^2 - 4y^2\) is also a difference of squares:
x^2 - 4y^2 = (x - 2y)(x + 2y)
The term \(x^2 + 4y^2\) cannot be factored over the reals.
Thus, the complete factorization is:
Final answer: \(\boxed{(x - 2y)(x + 2y)(x^2 + 4y^2)}\)
A sequence of five real numbers forms an arithmetic progression, and t...
a - 6, \quad a - 3, \quad a, \quad a + 3, \quad a + 6
Since the middle term is given as 2, we have \(a = 2\).
So the terms are:
-4, \quad -1, \quad 2, \quad 5, \quad 8

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