To confirm it’s a maximum, check the sign of \( I'(t) \): decreasing before \( t = \sqrt10 \), increasing after? Actually, the numerator \( -1000t^2 + 10000 \) is positive for \( t < \sqrt10 \) and negative for \( t > \sqrt10 \), so \( I'(t) \) changes from positive to negative — maximum at \( t = \sqrt10 \). - Appfinity Technologies