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Home » Thus, the sum of all odd divisors of the number is \(\boxed192\). - Appfinity Technologies

Thus, the sum of all odd divisors of the number is \(\boxed192\). - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Setting \( f'(x) = 0 \) for critical points:
3x^2 - 12x + 9 = 0 \Rightarrow x^2 - 4x + 3 = 0 \Rightarrow (x-3)(x-1)...
So \( x = 1 \) and \( x = 3 \) are critical points.
Check \( f(1) = 2 \):
f(1) = 1^3 - 6(1)^2 + 9(1) + c = 1 - 6 + 9 + c = 4 + c
+ c = 2 \Rightarrow c = -2
#### #### -2
Find the radius of a circle if the circumference is equal to the area.
Solution 9:
Let the radius be \( r \).

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