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Home » Solving for \( w \), we find \( w = 10 \). - Appfinity Technologies

Solving for \( w \), we find \( w = 10 \). - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Now $\gcd(21, 19305)$: $19305 \div 21 = 919.285...$, $21 \cdot 919 = 1...
$\gcd(21, 6) = 3$
So GCD so far is $3$ — but we must check if $3$ is always a divisor.
But earlier logic: in any four consecutive odd integers, one is divisi...
Thus, always divisible by 3.
But not by 9, as shown.
Is it divisible by any higher number? Try divisibility by 15? No — $1...
Similarly, not divisible by 7: $9,11,13,15$: product $9\cdot11=99, 13\...
So only guaranteed prime factor is 3. And we have at least $3^1$.
But wait: is it divisible by $9$ always? No, as $105 = 3 \cdot 5 \cdot...

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