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Home » So solution: \( x < -3 \) or \( x > 4 \) - Appfinity Technologies

So solution: \( x < -3 \) or \( x > 4 \) - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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🔥 Popular Posts

The x-coordinate of the vertex is given by \( x = -\frac{b}{2a} \), wh...
\( x = -\frac{-12}{2 \times 3} = \frac{12}{6} = 2 \).
Substituting \( x = 2 \) into the function, \( f(2) = 3(2)^2 - 12(2) +...
Thus, the vertex is \( (2, -5) \).
Solve the exponential equation \( 2^{3x} = 64 \).
Express 64 as a power of 2: \( 64 = 2^6 \).
Therefore, \( 2^{3x} = 2^6 \).
Since the bases are the same, equate the exponents: \( 3x = 6 \).
Solving for \( x \), \( x = \frac{6}{3} = 2 \).
The diameter of the circle is equal to the side length of the square,...

📝 Recent Posts

Substitute: \( c^2 = 9^2 + 12^2 = 81 + 144 = 225 \).
So, \( c = \sqrt{225} = 15 \).
The sum of the first \( n \) positive integers is 210. What is \( n \)...
Use the formula \( \frac{n(n+1)}{2} = 210 \).
Multiply both sides by 2: \( n(n+1) = 420 \).
Solve the quadratic: \( n^2 + n - 420 = 0 \).
Factor: \( (n - 20)(n + 21) = 0 \).
Positive solution: \( n = 20 \).
A car depreciates in value by 15% per year. If it is worth $20,000 now...
Use exponential decay: \( V = 20000 \times (1 - 0.15)^3 \).

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