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Home » Maximum is $f(5) = 120$ kN. - Appfinity Technologies

Maximum is $f(5) = 120$ kN. - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Question: A transportation analyst is analyzing a network with 6 red b...
We are selecting 5 buses from a total of $ 6 + 4 + 5 = 15 $ buses.
We want the probability that the selection includes **at least two bus...
### Step 1: Total number of ways to choose 5 buses from 15:
\text{Total ways} = \binom{15}{5} = 3003
### Step 2: Favorable outcomes — at least two of each color
We are looking for selections with **at least 2 red, 2 green, and 2 bl...
Thus, the number of favorable outcomes is:
### Step 3: Compute the probability
P(\text{at least 2 of each color}) = \frac{0}{3003} = 0

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