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Home » G: $eginpmatrix -1 & -1 \ 1 & 1 \endpmatrix$ - Appfinity Technologies

G: $eginpmatrix -1 & -1 \ 1 & 1 \endpmatrix$ - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Now subtract (5) from (6):
Subtract (6) from (7):
Now subtract (8) from (9):
Substitute into (8):
6\left(-\frac{4}{3}\right) + b = \frac{9}{2} \Rightarrow -8 + b = \fra...
Now use (5):
7\left(-\frac{4}{3}\right) + 3\left(\frac{25}{2}\right) + c = -4 \Righ...
Find common denominator (6):
-\frac{56}{6} + \frac{225}{6} + c = -4 \Rightarrow \frac{169}{6} + c =...
a + b + c + d = 3 \Rightarrow -\frac{4}{3} + \frac{25}{2} - \frac{193}...

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The vertex \( (h, k) \) of a parabola \( ax^2 + bx + c \) is given by:
\[ h = -\frac{b}{2a} \]
Here, \( a = 3 \), \( b = -12 \).
Calculate \( h \):
\[ h = -\frac{-12}{2 \times 3} = \frac{12}{6} = 2 \]
Substitute \( x = 2 \) into \( f(x) \) to find \( k \):
\[ k = 3(2)^2 - 12(2) + 7 = 12 - 24 + 7 = -5 \]
The vertex is \( (2, -5) \).
#### (2, -5)
3x + 4y &= 10 \\

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