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Home » \cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \frac12 - Appfinity Technologies

\cos(\theta + 60^\circ) + \cos(\theta - 60^\circ) = \frac12 - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📝 Recent Posts

\[ A = \pi r^2 = \pi (5)^2 = 25\pi \text{ square meters} \]
Hence, the area of the circular garden is \(\boxed{25\pi}\) square met...
Question:** A mammalogist studying the Arctic tundra uses a triangular...
For a right triangle, the radius \( r \) of the inscribed circle can b...
\[ r = \frac{a + b - c}{2} \]
where \( a \) and \( b \) are the legs and \( c \) is the hypotenuse....
\[ c = \sqrt{a^2 + b^2} = \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{...
Substitute the values into the formula for the radius:
\[ r = \frac{5 + 12 - 13}{2} = \frac{4}{2} = 2 \text{ meters} \]
Thus, the radius of the inscribed circle is \(\boxed{2}\) meters.

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