But if the "order" refers only to the application of the operation (i.e., 2 positions are distinct for pumping), the count is $ \binom74 \cdot \binom42 \cdot \frac4!2! = 35 \cdot 6 \cdot 12 = 2520 $. Clarifying the problem's intent, the most plausible interpretation leads to $\boxed2520$. - Appfinity Technologies