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Home » A = 5000 Ã (1 + 0,02)^12 - Appfinity Technologies

A = 5000 Ã (1 + 0,02)^12 - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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n^2 = (10k + 4)^2 = 100k^2 + 80k + 16 \equiv 80k + 16 \pmod{100}
We want \( 80k + 16 \equiv 76 \pmod{100} \), so:
80k \equiv 60 \pmod{100}
Divide by 20:
4k \equiv 3 \pmod{5} \implies k \equiv 2 \pmod{5} \quad \text{(since }...
Thus, \( k = 5m + 2 \), so \( n = 10(5m + 2) + 4 = 50m + 24 \). The sm...
Now consider \( n \equiv 6 \pmod{10} \): \( n = 10k + 6 \).
n^2 = 100k^2 + 120k + 36 \equiv 20k + 36 \pmod{100}
Set \( 20k + 36 \equiv 76 \pmod{100} \):
20k \equiv 40 \pmod{100} \implies k \equiv 2 \pmod{5}

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