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3z = 20 - 5 - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Question: A sequence of five real numbers forms an arithmetic progress...
Let the five terms of the arithmetic progression be:
a - 2d, \, a - d, \, a, \, a + d, \, a + 2d
First term + Fifth term: $(a - 2d) + (a + 2d) = 2a = 14 \Rightarrow a...
Second term + Fourth term: $(a - d) + (a + d) = 2a = 10$
But this contradicts $2a = 14$. So letâs double-check the assumption...
Actually, the second and fourth terms: $(a - d) + (a + d) = 2a = 10 \R...
So from the first condition: first + fifth = $2a = 14 \Rightarrow a =...
Contradiction. So both cannot be true unless we made a mistake.
Letâs re-express the sequence as:

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