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Home » \( P \approx 1200 \times 1.7623 = 2,114.76 \) - Appfinity Technologies

\( P \approx 1200 \times 1.7623 = 2,114.76 \) - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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Substitute $ a = 0 $ into (A): $ 6(0) + b = 2 \Rightarrow b = 2 $.
Substitute $ a = 0, b = 2 $ into Eq 1:
7(0) + 3(2) + c = 7 \Rightarrow 6 + c = 7 \Rightarrow c = 1.
Now use $ p(1) $: $ 0 + 2 + 1 + d = 3 \Rightarrow d = 0 $.
Thus, $ p(x) = 2x^2 + x $. Then $ p(0) = 0 $.
But wait—this is quadratic, but the problem states $ p(x) $ is cubic....
Wait—perhaps the problem allows degree ≤ 3. Many contest problems phra...
But let's verify all values:
$ p(1) = 2 + 1 = 3 $,
$ p(2) = 8 + 2 = 10 $,

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