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Home » \[ 2a = 1 \] - Appfinity Technologies

\[ 2a = 1 \] - Appfinity Technologies

📅 March 1, 2026 👤 scraface

Mar 01, 2026

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📌 f(g(x)) = f(\sqrt{x+3}) = (\sqrt{x+3})^2 + 2\sqrt{x+3} + 1

📌 Simplify the expression:

📌 f(g(x)) = x + 3 + 2\sqrt{x+3} + 1 = x + 2\sqrt{x+3} + 4

📌 Now find \( f(g(5)) \):

📌 g(5) = \sqrt{5+3} = \sqrt{8} = 2\sqrt{2}

📌 Substitute into \( f(x) \):

📌 f(g(5)) = (2\sqrt{2})^2 + 2(2\sqrt{2}) + 1 = 8 + 4\sqrt{2} + 1 = 9 + 4\sqrt{2}

📌 \boxed{9 + 4\sqrt{2}}

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